ASM program to find the smallest number in an array of data using 8085

AIM: To find the smallest number in an array of data using 8085 instruction set.

ALGORITHM:

1. Load the address of the first element of the array in HL pair
2. Move the count to B – reg.
3. Increment the pointer
4. Get the first data in A – reg.
5. Decrement the count.
6. Increment the pointer
7. Compare the content of memory addressed by HL pair with that of A – reg.
8. If carry = 1, go to step 10 or if Carry = 0 go to step 9
9. Move the content of memory addressed by HL to A – reg.
10. Decrement the count
11. Check for Zero of the count. If ZF = 0, go to step 6, or if ZF = 1 go to next step.
12. Store the smallest data in memory.
13. Terminate the program.

PROGRAM:

       LXI H,4200 ;Set pointer for array 
       MOV B,M    ;Load the Count
       INX H
       MOV A,M    ;Set 1st element as largest data
       DCR B      ;Decrement the count
LOOP:  INX H
       CMP M      ;If A-reg < M go to AHEAD
       JC AHEAD
       MOV A,M    ;Set the new value as largest
AHEAD: DCR B
       JNZ LOOP   ;Repeat comparisons till count = 0
       STA 4300   ;Store the largest value at 4300
       HLT

OBSERVATION:

Input:	05 (4200)
	0A (4201)
	F1 (4202)
	1F (4203)
	26 (4204)
	FE (4205)
Output:	0A (4300)

RESULT:

Thus the program to find the smallest number in an array of data was executed.