77. Predict the output or error(s) of the following c code

1
2
3
4
5
6
7
8
9
10
11
12

struct point
{
	int x;
	int y;
};
struct point origin,*pp;
main()
{
	pp=&origin;
	printf("origin is(%d%d)\n",(*pp).x,(*pp).y);
	printf("origin is (%d%d)\n",pp->x,pp->y);
}

Answer:
origin is(0,0)
origin is(0,0)

Explanation:
pp is a pointer to structure. we can access the elements of the structure either with arrow mark or with indirection operator.

Note:
Since structure point is globally declared x & y are initialized as zeroes