53. Predict the output or error(s) of the following c code

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 main()
{
	int  i, n;
	char *x = “girl”;
	n = strlen(x);
	*x = x[n];
	for(i=0; i<n; ++i)
	{
		printf(“%s\n”,x);
		x++;
	}
}

Answer:
(blank space)
irl
rl
l

Explanation:
Here a string (a pointer to char) is initialized with a value “girl”. The strlen function returns the length of the string, thus n has a value 4. The next statement assigns value at the nth location (‘\0’) to the first location. Now the string becomes “\0irl” . Now the printf statement prints the string after each iteration it increments it starting position. Loop starts from 0 to 4. The first time x[0] = ‘\0’ hence it prints nothing and pointer value is incremented. The second time it prints from x[1] i.e “irl” and the third time it prints “rl” and the last time it prints “l” and the loop terminates.