1
2
3
4
5
6
7
8
9
10
11
12
13
| main()
{
int c[ ]={2.8,3.4,4,6.7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++){
printf(" %d ",*c);
++q;
}
for(j=0;j<5;j++){
printf(" %d ",*p);
++p;
}
} |
main()
{
int c[ ]={2.8,3.4,4,6.7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++){
printf(" %d ",*c);
++q;
}
for(j=0;j<5;j++){
printf(" %d ",*p);
++p;
}
}
Click here to view the answer
Answer:
2 2 2 2 2 2 3 4 6 5
Explanation:
Initially pointer c is assigned to both p and q. In the first loop, since only q is incremented and not c , the value 2 will be printed 5 times. In second loop p itself is incremented. So the values 2 3 4 6 5 will be printed.