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| #define clrscr() 100
main()
{
clrscr();
printf("%d\n",clrscr());
} |
#define clrscr() 100
main()
{
clrscr();
printf("%d\n",clrscr());
}
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Answer:
100
Explanation:
Preprocessor executes as a seperate pass before the execution of the compiler. So textual replacement of clrscr() to 100 occurs.The input program to compiler looks like this :
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| main()
{
100;
printf("%d\n",100);
} |
main()
{
100;
printf("%d\n",100);
}
Note:
100; is an executable statement but with no action. So it doesn’t give any problem.
