Write a C++ program to calculate a to the power b without using power function.
#include<iostream.h> #include<conio.h> void main() { int a,b,i,temp=1; clrscr(); cout<<"Enter number for operation"; cin>>a>>b; for(i=1;i<=b;i++) { temp=temp*a; } cout<<endl<<"Result are:: "<<temp; getch(); } |
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Above program gives wrong answers as well as they occupy high memory any more time to type the simple program is
# include
void main()
{
int a;
cout<>a;
cout<<"\n power of "<<a<<" is "<<a*a;
}
SORRY GUYS I MISTAKED IN ABOVE PROGRAM THE CORRECT CODE IS HERE
#include
void main()
{
int a;
cin>>a;
cout<<"\n power of "<<a<<" is
"<<a*a;
}
thanks
This problem can be solved by applying different methods.
1st Method:
#include
#include
void main()
{
int a,b,c,i;
clrscr;
printf(“Enter the base: “);
scanf(“%d”,&a);
printf(“Enter the power: “);
scanf(“%d”,&b);
c=a;
for(i=1;i<b;i++)
{
c=c*a;
}
printf("Result = %d",c);
getch();
}
2nd Method:
#include
#include
void power(int a, int b);
void main()
{
int a,b;
clrscr();
printf(“Enter the base: “);
scanf(“%d”,&a);
printf(“Enter the power: “);
scanf(“%d”,&b);
power(a,b);
getch();
}
void power(int a, int b)
{
int c;
c=a;
for(i=1;i<b;i++)
{
c=c*a;
}
printf("Result = %d",c);
}
There are so many different methods to solve this problem.
#include
#include
int main ()
{
int a,b,i,temp=1;
printf (“enter value :”);
scanf (“%d”,&a);
printf ( “enter power value :”);
scanf (“%d”,&b);
for (i=1;i<=b;i++)
{
temp= a*temp;
}
printf("vlaue is :%d", temp);
getch();
return 0;
}
this is easiest one take copy pencil insert value in loop and see how ezily it will
Thanx Guys.
U r doing great.
how to find power of number without using pow function and multiplication operator ?
Write a program to find power of a number ( exponent value should be negative or 0.)
#include
#include
using namespace std;
int main() {
int exp;
float base;
cout <> base >> exp;
cout << "Result = " << pow(base, exp);
return 0;
}
int main ()
{ int b, a;
for ( int n=1; n<=a; n++)
{b=a*n;
}
count<<b;}
why did it not run?