Palindrome checking using function overloading

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#include "iostream"
using namespace std;
#include "conio.h"
#include "string.h"
class func
{
public:
void pal(int );
void pal(char c[]);
};
void func :: pal(int n)
{
int n1,sum,a;
n1=n;
sum=0;
 
do
{
sum=sum*10;
a=n%10;
sum=sum+a;
n=n/10;
}while(n>0);
if(sum==n1)
cout<<"\n it is Palindrom";
else
cout<<"\n it is not a palindrom";
 
}
void func :: pal(char c[])
{
int l=strlen(c);
char b[10];
int i,j;
for(i=0,j=l-1;i<l;i++,j–)
{
b[i]=c[j];
}
b[i]='';
if(strcmp(c,b)==0)
{cout<<"\nThe entered text is palindrome";
}
else
{cout<<"\n the entered text is not a palindrome";
}
}
int main()
{
char c[10];
int k,r,v;
func p;
do
{
cout<<"palindrome"<<endl;
cout<<"1.for interger"<<endl;
cout<<"2.for character"<<endl;
cout<<"enter the choice\n"<<endl;
cin>>r;
switch(r)
{
case 1:
cout<<"Enter the number";
cin>>k;
p.pal(k);
break;
 
case 2:
cout<<"\nEnter the string to be checked"<<endl;
cin>>c;
p.pal(c);
break;
}
cout<<"\ndo you want to continue? (1/0)"<<endl;
cin>>v;
}while(v==1);
getch();
}
sathish kumar

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