Source Codes | Student Projects

C Program for Infix to Prefix Conversion

Ansten Lobo — Sat, 09 Jun 2012 16:57:15 +0000

C Program for Infix to Prefix Conversion.
Source: Dr. G T Raju, Professor & Head, Dept. of CSE, RNSIT

#define SIZE 50            /* Size of Stack */
#include
#include 
char s[SIZE];
int top=-1;       /* Global declarations */

push(char elem)
{                       /* Function for PUSH operation */
    s[++top]=elem;
}

char pop()
{                      /* Function for POP operation */
    return(s[top--]);
}

int pr(char elem)
{                 /* Function for precedence */
    switch(elem)
    {
    case '#': return 0;
    case ')': return 1;
    case '+':
    case '-': return 2;
    case '*':
    case '/': return 3;
    }
}

main()
{                         /* Main Program */
    char infx[50],prfx[50],ch,elem;
    int i=0,k=0;
    printf("\n\nRead the Infix Expression ? ");
    scanf("%s",infx);
    push('#');
    strrev(infx);
    while( (ch=infx[i++]) != '\0')
    {
        if( ch == ')') push(ch);
        else
            if(isalnum(ch)) prfx[k++]=ch;
            else
                if( ch == '(')
                {
                    while( s[top] != ')')
                        prfx[k++]=pop();
                    elem=pop(); /* Remove ) */
                }
                else
                {       /* Operator */
                    while( pr(s[top]) >= pr(ch) )
                        prfx[k++]=pop();
                    push(ch);
                }
    }
    while( s[top] != '#')     /* Pop from stack till empty */
        prfx[k++]=pop();
    prfx[k]='\0';          /* Make prfx as valid string */
    strrev(prfx);
    strrev(infx);
    printf("\n\nGiven Infix Expn: %s  Prefix Expn: %s\n",infx,prfx);
}

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Verilog HDL Program for D Flip Flop

Ansten Lobo — Sat, 09 Jun 2012 06:44:59 +0000

A flip-flop or latch is a circuit that has two stable states and can be used to store state information. The circuit can be made to change state by signals applied to one or more control inputs and will have one or two outputs. It is the basic storage element in sequential logic. Flip-flops and latches are a fundamental building block of digital electronics systems used in computers, communications, and many other types of systems.

he D flip-flop captures the value of the D-input at a definite portion of the clock cycle (such as the rising edge of the clock). That captured value becomes the Q output. At other times, the output Q does not change. The D flip-flop can be viewed as a memory cell, a zero-order hold, or a delay line.

module d(q,q1,d,c);
output q,q1;
 input d,c;
 reg q,q1;
	initial 
	   begin
		   q=1'b0; q1=1'b1;
	  end
	always @ (posedge c)
	   begin 
		 q=d;
		 q1= ~d;
	   end
endmodule

Simulated waveform for D Flip Flop

The post Verilog HDL Program for D Flip Flop first appeared on Student Projects.

How to align or format codes in Visual Studio?

Editorial Team — Thu, 11 Aug 2011 08:14:15 +0000

This is very simple in Visual Studio. Follow the below steps.

Select the code you want to re-format.
Press Ctrl-K
Press Ctrl-F

The key combination Ctrl-K + Ctrl-F only works on selected text, so make sure you select the code you want to re-format before using it. You can easily reformat the entire code by pressing Ctrl-A Ctrl-K Ctrl-F.

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Java program to display triangle 1 24 369 481216

surajk — Sat, 05 Feb 2011 13:29:29 +0000

/* Display Triangle as follow

   1

   2 4

   3 6 9

   4 8 12 16 ... N (indicates no. of Rows) */

class Output3{

	public static void main(String args[]){

		int n = Integer.parseInt(args[0]);

		for(int i=1;i<=n;i++){
			for(int j=1;j<=i;j++){
				System.out.print((i*j)+" ");
			}
			System.out.print("\n");
		}
	}
}

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Java program to display triangle 0 10 101 0101

surajk — Sat, 05 Feb 2011 13:28:49 +0000

/* Display Triangle as follow
   0
   1 0
   1 0 1
   0 1 0 1 */
class Output2{
	public static void main(String args[]){
		for(int i=1;i<=4;i++){
			for(int j=1;j<=i;j++){
				System.out.print(((i+j)%2)+" ");
			}
			System.out.print("\n");
		}
	}
}

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Java program to display triangle 1 23 456 78910

surajk — Sat, 05 Feb 2011 13:28:09 +0000

/* Display Triangle as follow : BREAK DEMO.
   1
   2 3
   4 5 6
   7 8 9 10 ... N */
class Output1{
	public static void main(String args[]){
		int c=0;
		int n = Integer.parseInt(args[0]);
loop1: for(int i=1;i<=n;i++){
loop2: for(int j=1;j<=i;j++){
	       if(c!=n){
		       c++;
		       System.out.print(c+" ");
	       }
	       else
		       break loop1;
       }
       System.out.print("\n");
       }
	}
}

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Java program to find average of consecutive N Odd no. and Even no.

surajk — Sat, 05 Feb 2011 13:27:21 +0000

class EvenOdd_Avg{
	public static void main(String args[]){
		int n = Integer.parseInt(args[0]);
		int cntEven=0,cntOdd=0,sumEven=0,sumOdd=0;
		while(n > 0){
			if(n%2==0){
				cntEven++;
				sumEven = sumEven + n;
			}
			else{
				cntOdd++;
				sumOdd = sumOdd + n;
			}
			n--;
		}
		int evenAvg,oddAvg;
		evenAvg = sumEven/cntEven;
		oddAvg = sumOdd/cntOdd;
		System.out.println("Average of first N Even no is "+evenAvg);
		System.out.println("Average of first N Odd no is "+oddAvg);
	}
}

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Java program to generate Harmonic Series 1 + 1/2 + 1/3 + 1/4 + 1/5

surajk — Sat, 05 Feb 2011 13:26:35 +0000

/* Write a program to generate Harmonic Series.
   Example :
   Input - 5
   Output - 1 + 1/2 + 1/3 + 1/4 + 1/5 = 2.28 (Approximately) */
class HarmonicSeries{
	public static void main(String args[]){
		int num = Integer.parseInt(args[0]);
		double result = 0.0;
		while(num > 0){
			result = result + (double) 1 / num;
			num--;
		}
		System.out.println("Output of Harmonic Series is "+result);
	}
}

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Java program to demonstrate switch case

surajk — Sat, 05 Feb 2011 13:25:41 +0000

/* switch case demo
   Example :
   Input - 124
   Output - One Two Four */
class SwitchCaseDemo{
	public static void main(String args[]){
		try{
			int num = Integer.parseInt(args[0]);
			int n = num; //used at last time check
			int reverse=0,remainder;
			while(num > 0){
				remainder = num % 10;
				reverse = reverse * 10 + remainder;
				num = num / 10;
			}
			String result=""; //contains the actual output
			while(reverse > 0){
				remainder = reverse % 10;
				reverse = reverse / 10;
				switch(remainder){
					case 0 :
						result = result + "Zero ";
						break;
					case 1 :
						result = result + "One ";
						break;
					case 2 :
						result = result + "Two ";
						break;
					case 3 :
						result = result + "Three ";
						break;
					case 4 :
						result = result + "Four ";
						break;
					case 5 :
						result = result + "Five ";
						break;
					case 6 :
						result = result + "Six ";
						break;
					case 7 :
						result = result + "Seven ";
						break;
					case 8 :
						result = result + "Eight ";
						break;
					case 9 :
						result = result + "Nine ";
						break;
					default:
						result="";
				}
			}
			System.out.println(result);
		}catch(Exception e){
			System.out.println("Invalid Number Format");
		}
	}
}

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Java program to find whether no. is palindrome or not

surajk — Sat, 05 Feb 2011 13:24:43 +0000

/* Write a program to find whether no. is palindrome or not.
   Example :
   Input - 12521 is a palindrome no.
   Input - 12345 is not a palindrome no. */
class Palindrome{
	public static void main(String args[]){
		int num = Integer.parseInt(args[0]);
		int n = num; //used at last time check
		int reverse=0,remainder;
		while(num > 0){
			remainder = num % 10;
			reverse = reverse * 10 + remainder;
			num = num / 10;
		}
		if(reverse == n)
			System.out.println(n+" is a Palindrome Number");
		else
			System.out.println(n+" is not a Palindrome Number");
	}
}

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