Java program that checks whether the given string is palindrome or not

27 thoughts on “Java program that checks whether the given string is palindrome or not”

1. Watevr Bullshits….nthng appropriate…jst a waste of tym….losrs!!!!!!!!

2. import java.util.Scanner;
   public class PalindromeSentence

   {
   public static void main( String[] argv )
   {
   System.out.print( “Enter your phrase: ” );
   String phrase = new Scanner(System.in).nextLine();
   String eval = phrase.toLowerCase();
   boolean isPalindrome = true;
   int first , last;
   for( first=0 , last=eval.length()-1 ; first < last ; first++ , last– )
   {
   while( (int)eval.charAt(first) ‘z’ ) first++;
   while( (int)eval.charAt(last ) ‘z’ ) last–;
   if( first > last || eval.charAt(first) != eval.charAt(last) ) isPalindrome = false;
   }
   System.out.printf( “\”%s\” is%s a palindrome.\n”, phrase, (isPalindrome ? “” : ” not” ) );
   }
   }

3. class palindrome
   {

   public static void main(String[] args)
   {
   String str = “malayalam”; // write a string name

   StringBuffer sb = new StringBuffer(str).reverse();

   String strRev = sb.toString();

   if(str.equalsIgnoreCase(strRev))
   {
   System.out.println(” given string is Palindrome”);
   }
   else
   {
   System.out.println(” given string is Not a Palindrome”);
   }
   }
   }
   OUTPUT
   GIVEN STRING IS PALINDROME

4. all sucking program nothing will compile

5. Im getting an error in StringBuffer example….
   Exception in thread “main” java.lang.ArrayIndexOutOfBoundsException: 0
   at Pallindrome.main(Pallindrome.java:10)

6. nee amma pukula sulli
   okkati complie kadhu

7. excelent

8. i have written the program but i am facing problem to run it

9. this is helpful .. thanks guys.. God bless !!

10. import java.lang.*;
    import java.io.*;
    class palindrome
    {
    public static void main(String[]args) throws IOException
    {
    String str;
    BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
    System.out.println(“enter the string”);
    str=br.readLine();
    StringBuffer sb=new StringBuffer(str);
    String strRev=new String(sb.reverse());
    if(str.equalsIgnoreCase (strRev))
    {
    System.out.println(“it is a palindrome”);
    }
    else
    {
    System.out.println(“it is not a palindrome”);
    }
    }
    }

11. Simplest of all above—–>

    public Palindrome(String first,String second)
    {
    this.f1=first;
    this.f2=second;
    int num1=f1.length();
    int num2=f2.length();
    char a=f1.charAt(0);
    char b=f2.charAt(num2-1);

    if (num1==num2)
    {
    for(int i=0;i=0;j–)
    {char d=f2.charAt(j);
    if(c==d)
    {
    if(i==num1-1)
    {System.out.println(“Palindrome”);
    }

    }

    }

    }
    }
    else
    {System.out.println(“Not Palindrome”);}
    }

12. public Palindrome(String first,String second)
    {
    this.f1=first;
    this.f2=second;
    int num1=f1.length();
    int num2=f2.length();
    char a=f1.charAt(0);
    char b=f2.charAt(num2-1);

    if (num1==num2)
    {
    for(int i=0;i=0;j–)
    {char d=f2.charAt(j);
    if(c==d)
    {
    if(i==num1-1)
    {System.out.println(“Palindrome”);
    }

    }

    }

    }
    }
    else
    {System.out.println(“Not Palindrome”);}
    }

13. class Palindrome
    {
    public void input(String s)
    {
    boolean result=false;
    String reverse=””;
    for(int i=s.length()-1;i>=0;i–)
    {
    char ans=s.charAt(i);
    reverse=reverse+ans;
    result=s.equals(reverse);
    if(result==true)
    System.out.println(s+”is palindrome”);
    else
    System.out.println(s+”is not palindrome”);
    }
    }
    }

14. public class Conversion1 {
    public static void main(String[] args)
    {
    int i;
    String s2=””;
    String s1 = new String(“coffoc”);

    int len_str = s1.length();
    for(i=len_str-1;i>=0;i–)
    {
    s2 = s2+s1.charAt(i);
    }
    System.out.println(“Hence reverse of the string is:”+s2);

    if(String.valueOf(s1).compareTo(String.valueOf(s2))==0)
    System.out.println(“Palindrome”);

    else
    System.out.println(“Not Palindrome”);
    }
    }

15. Nice guys,this is very useful to me

16. if the given String is not a palindrome? how will you change it into a palindrome?

17. Check this link > http://www.msccomputerscience.com/2014/05/java-program-to-check-whether-string-is.html

18. public class String2 {

    public static void main(String[] args) {
    java.util.Scanner scn=new java.util.Scanner(System.in);
    System.out.println(“enter a name”);
    String s4=scn.nextLine();

    String s2=””;

    int m=s4.length();
    System.out.println(m);
    for(int i=m-1;i>=0;i–)
    {
    s2=s2+s4.charAt(i);

    }
    System.out.println(“reverse string=”+s2);

    boolean x=s4.equalsIgnoreCase(s2);
    if (x==true)
    {
    System.out.println(“Palindrome”);

    }
    else
    System.out.println(“its not a Palindrome”);

    }
    }

19. public class Palindrome {

    public static void main(String[] args) {
    StringBuffer string = new StringBuffer(“malayalam”);
    if (string.substring(0).equals(string.reverse().toString()))
    System.out.println(“String is palindrom”);
    else
    System.out.println(“String is NOT palindrom”);

    }
    }

20. public class Palindrome {

    public static void main(String[] args) {
    StringBuffer string = new StringBuffer(“malayalam”);
    if (string.substring(0).equals(string.reverse().toString()))
    System.out.println(“String is palindrom”);
    else
    System.out.println(“String is NOT palindrom”);

    }
    }

21. public class Palindrome {

    public static void main(String[] args) {
    StringBuffer string = new StringBuffer(“malayalam”);
    if (string.substring(0).equals(string.reverse().toString()))
    System.out.println(“String is palindrom”);
    else
    System.out.println(“String is NOT palindrom”);

    }
    }

22. Another Simple one without importing any API’s,

    public class FindPalindromeOrNot {

    public static void main(String[] ar) {

    String inputString = “liril”;

    boolean isPalindrome = true;
    char[] inputStringArr = inputString.toCharArray();
    int length = inputStringArr.length;
    int temp = length;
    for (int n = 0; n < length; n++) {
    temp -= 1;
    if (inputStringArr[n] != inputStringArr[temp]) {
    isPalindrome = false;
    }

    }

    System.out.println("Is Palindrome = " + isPalindrome);

    }
    }

23. how do I make a program to show if word, sentence or number is palindrome

24. check Simple and easy program to find palindrome here http://www.javaengineeringprograms.com/program-to-check-palindrome-in-java/

25. Simple program. One more way to check string or number palindrome is http://www.explain-java.com/write-a-java-program-to-check-a-numberstring-is-palindrome-or-not-with-output/