Comments on: C++ program to calculate a to the power b without using power function

By: Pop

Pop — Wed, 07 Oct 2015 03:10:23 +0000

why did it not run?

By: Mayank Pathania

Mayank Pathania — Mon, 14 Sep 2015 18:23:45 +0000

int main ()
{ int b, a;
for ( int n=1; n<=a; n++)
{b=a*n;
}
count<

By: anita

anita — Tue, 04 Aug 2015 07:01:05 +0000

In reply to navin kumar.

#include
#include
using namespace std;

int main() {
int exp;
float base;

cout <> base >> exp;

cout << "Result = " << pow(base, exp);
return 0;
}

By: anita

anita — Tue, 04 Aug 2015 06:56:09 +0000

Write a program to find power of a number ( exponent value should be negative or 0.)

By: navin kumar

navin kumar — Sun, 01 Mar 2015 07:50:26 +0000

how to find power of number without using pow function and multiplication operator ?

By: AB

AB — Fri, 05 Dec 2014 15:15:41 +0000

Thanx Guys.
U r doing great.

By: bilal iplanetz.com 03335106003

bilal iplanetz.com 03335106003 — Mon, 29 Sep 2014 17:55:11 +0000

this is easiest one take copy pencil insert value in loop and see how ezily it will

By: bilal

bilal — Mon, 29 Sep 2014 17:53:07 +0000

#include
#include

int main ()
{
int a,b,i,temp=1;

printf (“enter value :”);
scanf (“%d”,&a);
printf ( “enter power value :”);
scanf (“%d”,&b);
for (i=1;i<=b;i++)
{
temp= a*temp;
}
printf("vlaue is :%d", temp);

getch();
return 0;
}

By: Priyam Gaurav

Priyam Gaurav — Tue, 05 Mar 2013 16:51:48 +0000

This problem can be solved by applying different methods.
1st Method:

#include
#include
void main()
{
int a,b,c,i;
clrscr;
printf(“Enter the base: “);
scanf(“%d”,&a);
printf(“Enter the power: “);
scanf(“%d”,&b);
c=a;
for(i=1;i {
c=c*a;
}
printf("Result = %d",c);
getch();
}

2nd Method:

#include
#include
void power(int a, int b);
void main()
{
int a,b;
clrscr();
printf(“Enter the base: “);
scanf(“%d”,&a);
printf(“Enter the power: “);
scanf(“%d”,&b);
power(a,b);
getch();
}
void power(int a, int b)
{
int c;
c=a;
for(i=1;i {
c=c*a;
}
printf("Result = %d",c);
}

There are so many different methods to solve this problem.

By: aarthy ravichandran

aarthy ravichandran — Sat, 16 Feb 2013 12:56:22 +0000

thanks