#include<stdio.h>
#include<conio.h>
int stlen(char str[50])
{
int len = 0;
while(str[len]!=’\0′)
len++;
len–;
return len;
}
void stcat(char str1[50], char str2[50])
{
int i = 0,len = 0;
while(str1[len]!=’\0′)
len++;
while(str2[i]!=’\0′)
{
str1[len] = str2[i];
i++;
len++;
}
str1[len] = ‘\0’;
}
void main()
{
char str1[50], str2[50], str3[50], temp[50];
int len1, len2, len3, i, j, match, k;
clrscr();
printf(“\n\n\t ENTER A SENTENCE…: “);
gets(str1);
len1 = stlen(str1);
printf(“\n\n\t ENTER A STRING WHICH YOU WANT TO DELETE…: “);
gets(str2);
len2 = stlen(str2);
printf(“\n\n\t ENTER A NEW STRING WHICH YOU WANT TO INSERT …: “);
gets(str3);
len3 = stlen(str3);
for(i=0;i<=len1;i++)
{
match = 1;
for(j=0;j<=len2;j++)
if(str2[j]!=str1[i+j])
{
match = 0;
break;
}
if(match)
{
for(k=0,j=i+len2+1;j<=len1;j++,k++)
temp[k] = str1[j];
temp[k] = ‘\0’;
for(j=0;j<=len3;j++)
str1[i+j] = str3[j];
str1[i+j] = ‘\0’;
stcat(str1,temp);
len1 = len1 – len2 +len3;
i = i + j;
}
}
printf(“\n\n\t OUTPUT IS…: “);
puts(str1);
getch();
}
Download exe and source code here.
To replace a word by another word in a given string
Editorial Team
We are a group of young techies trying to provide the best study material for all Electronic and Computer science students. We are publishing Microcontroller projects, Basic Electronics, Digital Electronics, Computer projects and also c/c++, java programs.
sir,
i need c program to delete substing like following string1=”concatenate”,string2=”cat”
string2 ll be deleted from string1 so result should be string1=”conenate”.can u give me the coding for thos sir…
please give a better idea about a program to replace two words
bad program. should have some easy solution
THIS PROGRAMMING CODE IS MORE EASIER THAN THIS ONE…
TRY IT GUYS… (^_^)
#include
#include
#include
#include
using namespace std;
int main()
{
string str;
vector a;
vector::iterator it;
char word[40];
cout<<"Please enter something :"<<endl;
gets(word);
int pos;
int length = strlen(word);
// copy the sentence into a vector
for(int i=0;i<length;i++)
{
str.push_back(word[i]);
if(word[i] == ' ' || i == length – 1 )
{
a.push_back(str);
str.clear();
continue;
}
}
cout<<"Please enter another string: "<>str;
cout<<"Enter the position to replace the word:"<>pos;
it = a.begin();
it = a.erase(it+pos);
it = a.begin();
a.insert(it+pos,str);
for(it = a.begin();it <a.end();it++)
{
cout<<*it<<" ";
}
cout<<endl;
system("pause");
}
A VERY EASY CODE…
USING POINTERS ARE MORE BETTER THAN NORMAL CODINGS
Hey faras raoof…Thanx for ur program. But There is something missing.
I write: A quick brown fox
// and replace fox with dog
The output comes like: A quick brown dog ——–fox
Why is this: ———-fox visible? :/ what should i decrement in order to get that array in place? Is this how u designed the program or its d garbage value which fits into the 2d array? plz help