Comments on: To count the number of words in a given string

By: koushik

koushik — Thu, 18 Dec 2014 05:54:56 +0000

if input is ” ” (only space) it is showing as output = 1, but it will 0. waiting for your reply with your help. thanks.

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By: shohan

shohan — Thu, 18 Sep 2014 16:46:42 +0000

your code give a lot of error

By: ranjith

ranjith — Tue, 13 Aug 2013 09:22:00 +0000

it was wrong code and i have the easiest code created by me….:)

By: sathish

sathish — Tue, 13 Aug 2013 09:12:01 +0000

wrong code….

By: AYYA SURESH

AYYA SURESH — Fri, 28 Jun 2013 14:12:51 +0000

in above program i place spaces betweeen evry word like nearly 5 spaces between each word so i write like that above without spaces….pls understand perfectly ..!!!!

By: AYYA SURESH

AYYA SURESH — Fri, 28 Jun 2013 14:11:09 +0000

public class StringDemo {
public static void main(String[] ar){
String str=” HAI hEllO HOw arE You hai bga jaja abjblkds jksdnsd dnjd dndn iddwd dbdb cjb “;
int count=0;
int a=0,e=0,i=0,o=0,u=0,b=0,c=0,d=0;
System.out.println(str);
//System.out.println(“No. of Characters =”+str.length());
str=str.trim();
//System.out.println(“No. of Characters =”+str.length());
for(int j=0,k=1;j if(str.charAt(j)=='a'||str.charAt(j)=='A'){
a++;
c++;
}
else if(str.charAt(j)=='e'||str.charAt(j)=='E'){
e++;
c++;
}
else if(str.charAt(j)=='i'||str.charAt(j)=='I'){
i++;
c++;
}
else if(str.charAt(j)=='o'||str.charAt(j)=='O'){
o++;
c++;
}
else if(str.charAt(j)=='u'||str.charAt(j)=='U'){
u++;
c++;
}
else{
b++;
}
if(str.charAt(j)==' '){
count++;
}
if((str.charAt(k-1)!=' '&& k d++;

}
}
System.out.println("No. of Characters (without Spaces)="+(str.length()-count));
System.out.println("No. of spaces: "+count);
// System.out.println("No. of Words: "+(count+1));
System.out.println("No. of Words: "+(d+1));
System.out.println("No. of consonants and Symbols(if any): "+(b-count));
System.out.println("No. of vowel's: "+c);
System.out.println("No. of 'a's: "+a);
System.out.println("No. of 'e's: "+e);
System.out.println("No. of 'i's: "+i);
System.out.println("No. of 'o's: "+o);
System.out.println("No. of 'u's: "+u);

}
}

OUTPUT :
HAI hEllO HOw arE You hai bga jaja abjblkds jksdnsd dnjd dndn iddwd dbdb cjb
No. of Characters (without Spaces)=62
No. of spaces: 31
No. of Words: 15
No. of consonants and Symbols(if any): 46
No. of vowel's: 16
No. of 'a's: 7
No. of 'e's: 2
No. of 'i's: 3
No. of 'o's: 3
No. of 'u's: 1

By: Joel

Joel — Sun, 03 Mar 2013 14:12:02 +0000

Why are you writing
if ( ( str[i] == ‘ ‘ && str[i+1] != ‘ ‘ ) || i == len )
PLEASE Explain………

By: mayuri

mayuri — Fri, 05 Oct 2012 13:22:09 +0000

u r adding unnecessary lines in d program which r not needed

By: om prakash

om prakash — Fri, 02 Apr 2010 18:03:00 +0000

Thax dear your code is totally correct