This is the program to count number of words in the entered sentence.
Logic: The logic behind this program is checking if the character in the sentence is a ‘blank’ and with the conditions that the next is not a blank character, or current character position is not equal to length of the sentence. If so, variable ‘words’ is incremented by one as one new word found.
#include<stdio.h>
#include<conio.h>
void main()
{
char str[50];
int words = 0, len = 0, i;
clrscr();
printf(“\n\n\t ENTER A STRING…: “);
gets(str);
while(str[len]!=’\0′)
len++;
len–;
for(i=0;i<=len;i++)
{
if ( ( str[i] == ‘ ‘ && str[i+1] != ‘ ‘ ) || i == len )
words++;
}
printf(“\n\t NUMBER OF WORDS IN THE ABOVE SENTENCE IS…: %d”, words);
getch();
}
Download exe and source code here.
Thax dear your code is totally correct
u r adding unnecessary lines in d program which r not needed
Why are you writing
if ( ( str[i] == ‘ ‘ && str[i+1] != ‘ ‘ ) || i == len )
PLEASE Explain………
public class StringDemo {
public static void main(String[] ar){
String str=” HAI hEllO HOw arE You hai bga jaja abjblkds jksdnsd dnjd dndn iddwd dbdb cjb “;
int count=0;
int a=0,e=0,i=0,o=0,u=0,b=0,c=0,d=0;
System.out.println(str);
//System.out.println(“No. of Characters =”+str.length());
str=str.trim();
//System.out.println(“No. of Characters =”+str.length());
for(int j=0,k=1;j<str.length();j++,k++){
if(str.charAt(j)=='a'||str.charAt(j)=='A'){
a++;
c++;
}
else if(str.charAt(j)=='e'||str.charAt(j)=='E'){
e++;
c++;
}
else if(str.charAt(j)=='i'||str.charAt(j)=='I'){
i++;
c++;
}
else if(str.charAt(j)=='o'||str.charAt(j)=='O'){
o++;
c++;
}
else if(str.charAt(j)=='u'||str.charAt(j)=='U'){
u++;
c++;
}
else{
b++;
}
if(str.charAt(j)==' '){
count++;
}
if((str.charAt(k-1)!=' '&& k<str.length())&& (str.charAt(k)==' ')){
d++;
}
}
System.out.println("No. of Characters (without Spaces)="+(str.length()-count));
System.out.println("No. of spaces: "+count);
// System.out.println("No. of Words: "+(count+1));
System.out.println("No. of Words: "+(d+1));
System.out.println("No. of consonants and Symbols(if any): "+(b-count));
System.out.println("No. of vowel's: "+c);
System.out.println("No. of 'a's: "+a);
System.out.println("No. of 'e's: "+e);
System.out.println("No. of 'i's: "+i);
System.out.println("No. of 'o's: "+o);
System.out.println("No. of 'u's: "+u);
}
}
OUTPUT :
HAI hEllO HOw arE You hai bga jaja abjblkds jksdnsd dnjd dndn iddwd dbdb cjb
No. of Characters (without Spaces)=62
No. of spaces: 31
No. of Words: 15
No. of consonants and Symbols(if any): 46
No. of vowel's: 16
No. of 'a's: 7
No. of 'e's: 2
No. of 'i's: 3
No. of 'o's: 3
No. of 'u's: 1
in above program i place spaces betweeen evry word like nearly 5 spaces between each word so i write like that above without spaces….pls understand perfectly ..!!!!
wrong code….
it was wrong code and i have the easiest code created by me….:)
your code give a lot of error
You ought to take part in a contest for one
of the greatest websites online. I will recommend this blog!
if input is ” ” (only space) it is showing as output = 1, but it will 0. waiting for your reply with your help. thanks.