Comments on: To check whether the given string is palindrome-method 2

By: SUMI

SUMI — Wed, 23 Feb 2011 16:35:17 +0000

9TH LINE IS USED FOR CALCULATING THE LENGTH OF THE STRING..

By: priya

priya — Mon, 24 Jan 2011 13:43:35 +0000

last program is working.easy to enderstand

By: noel

noel — Mon, 02 Aug 2010 17:29:15 +0000

i couldn’t understand the following part:
for(j=0;str[j]!=” “;j++)
j=j–;
i=0

By: lopa

lopa — Sat, 05 Jun 2010 06:17:24 +0000

i couldnt understand ur 9th number line// for(j=0;str[j]!=”;j++);
can u pls explain?

By: Chetan

Chetan — Sun, 17 Jan 2010 08:59:19 +0000

THIS THING ALSO WORKS !! EASILY UNDERSTANDABLE !!!

#include
#include
int main()
{
int i,j,check=0;
char str[100];

printf(“ENTER A STRING:\n”);
gets(str);
for(j=0;str[j]!=”;j++);
j=j-1;
i=0;
while(i<=j)
{
if(str[i]==str[j])
{
i=i+1;
j=j-1;
check=1;
}
else
{
check=0;
break;
}
}

if(check==1)
printf("PALINDROME:");
else
printf("NOT A PALINDROME\n");

getch();

}

By: Bird

Bird — Sat, 10 Oct 2009 07:58:29 +0000

It works fine but it is case sensitive. How to solve that?