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	Comments on: To find the fibonacci numbers below a given number.	</title>
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		By: Lenny		</title>
		<link>https://studentprojects.in/software-development/c-tutorials/c/number/to-find-the-fibonacci-numbers-below-a-given-number/comment-page-1/#comment-8954</link>

		<dc:creator><![CDATA[Lenny]]></dc:creator>
		<pubDate>Mon, 24 Sep 2012 15:34:34 +0000</pubDate>
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					<description><![CDATA[The algebraic proof does porvide certain insights as well. For example, it tells you that the property,F(n+1)^2 – F(n)*F(n+2) = –[F(n)^2 – F(n–1)*F(n+1)] for all n,is independent of the initial values F(1) = 1, F(2) = 1, and therefore that something like Cassini’s identity will hold for any choice of initial conditions.This property can be rewritten F(n+1)^2 + F(n)^2 = F(n)*F(n+2) + F(n–1)*F(n+1), which has a simple geometric interpretation:The area of the two squares*  *  *  *  *    *  *  **  *  *  *  *    *  *  **  *  *  *  *    *  *  **  *  *  *  **  *  *  *  *is the same as that of the two rectangles*  *  *  *  *  *  *  **  *  *  *  *  *  *  **  *  *  *  *  *  *  **  *  *  *  **  *  *  *  *]]></description>
			<content:encoded><![CDATA[<p>The algebraic proof does porvide certain insights as well. For example, it tells you that the property,F(n+1)^2 – F(n)*F(n+2) = –[F(n)^2 – F(n–1)*F(n+1)] for all n,is independent of the initial values F(1) = 1, F(2) = 1, and therefore that something like Cassini’s identity will hold for any choice of initial conditions.This property can be rewritten F(n+1)^2 + F(n)^2 = F(n)*F(n+2) + F(n–1)*F(n+1), which has a simple geometric interpretation:The area of the two squares*  *  *  *  *    *  *  **  *  *  *  *    *  *  **  *  *  *  *    *  *  **  *  *  *  **  *  *  *  *is the same as that of the two rectangles*  *  *  *  *  *  *  **  *  *  *  *  *  *  **  *  *  *  *  *  *  **  *  *  *  **  *  *  *  *</p>
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