C program which converts given expression into its post-fix format

Below C program converts a given expression into its post-fix format

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#include<stdio.h>
#include<ctype.h>
#include<conio.h>
char s[20];
int top=-1;
void main()
{
char str[20];
char ch;
int i;
char pop();
void push(char);
int precd(char);
s[top]='#';
clrscr();
printf("\n\t\tOUTPUT");
printf("\n\tEnter the expression:");
gets(str);
printf("\n\tpostfix notation:");
for(i=0;str[i]!='\0';i++)
{
if(isalpha(str[i]))
{
printf("%c",str[i]);
continue;
}
if(str[i]==')')
{
while((ch=pop())!='(')
printf("%c",ch);
}
else if(str[i]=='(')
push(str[i]);
else if(precd(str[i])<=precd(s[top]))
{
printf("%c",pop());
push(str[i]);
}
else
push(str[i]);
}
while(top>=0)
printf("%c",pop());
getch();
}
void push(char st)
{
s[++top]=st;
}
char pop()
{
char st;
st=s[top--];
return(st);
}
 
int precd(char s)
{
switch(s)
{
case '$':return(4);
case '*':
case '/': return(3);
case '+':
case '-': return(2);
case '(': return(1);
case '#': return(-1);
}
return(0);
}
Drithi

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