C Program to implement STACK operations using Linked Lists.
Source: Dr. G T Raju, Professor & Head, Dept. of CSE, RNSIT
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 | #include <stdlib.h> typedef struct node { int data; struct node *link; }NODE; void Push(int); int pop(); void Display(); NODE *top=NULL; /* Global Declarations */ main() { /* Main Program */ int opn,elem; do { clrscr(); printf("\n ### Linked List Implementation of STACK Operations ### \n\n"); printf("\n Press 1-Push, 2-Pop, 3-Display,4-Exit\n"); printf("\n Your option ? "); scanf("%d",&opn); switch(opn) { case 1: printf("\n\nRead the Element tobe pushed ?"); scanf("%d",&elem); Push(elem); break; case 2: elem=Pop(); if(elem != -1) printf(" Deleted Node(From Top)with the Data: %d\n",elem); break; case 3: printf("Linked List Implementation of Stack: Status:\n"); Display(); break; case 4: printf("\n\n Terminating \n\n"); break; default: printf("\n\nInvalid Option !!! Try Again !! \n\n"); break; } printf("\n\n\n\n Press a Key to Continue . . . "); getch(); }while(opn != 4); } void Push(int info) { NODE *temp; temp=(NODE *)malloc(sizeof(NODE)); if( temp == NULL) printf(" Out of Memory !! Overflow !!!"); else { temp->data=info; temp->link=top; top=temp; printf(" Node has been inserted at Top(Front) Successfully !!"); } } int Pop() { int info; NODE *t; if( top == NULL) { printf(" Underflow!!!"); return -1; } else { t=top; info=top->data; top=top->link; t->link=NULL; free(t); return(info); } } void Display() { NODE *t; if( top == NULL) printf("Empty Stack\n"); else { t=top; printf("Top->"); while(t) { printf("[%d]->",t->data); t=t->link; } printf("Null\n"); } } |
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1umae puriyala i am pavam from india
@vidhi: The implementation of Stack is given very clearly. It is like a single linked list with addition and deletion of nodes happening at the head.
In case of QUEUE, the addition happens at the Tail and the insertion happens at the head.
STACK:
head
[]—->[]—->[]—->[]
QUEUE:
head tail
[]—->[]—->[]—->[]
very good solution of stack using linked list it really helps me…thanku…
is there a overflow condition in stack , when it is implemented using linked list ?
becoz while implementing stack using linked list , “n” no of nodes can b created ?
stacks using single linked list is clear but it would be more better if stacks using single linked list to display the give integers in reverse & same order ,if mentioned .